Number of counters on IT = How much strengh is added on ice per counter (1 counter, 2 counters, ...)

2 = 2,2.

3 = 3, 4, 3.

4 = 4, 6, 6, 4.

5 = 5, 8, 9, 8, 5.

6 = 6, 10, 12, 12, 10, 6.

7 = 7, 12, 15, 16, 15, 12, 7.

8 = 8, 14, 18, 20, 20, 18, 14, 8.

9 = 9, 16, 21, 24, 25, 24, 21, 16, 9.

10 = 10, 18, 24, 28, 30, 30, 28, 24, 18, 10.

11 = 11, 20, 27, 32, 35, 36, 35, 32, 27, 20, 11.

12 = 12, 22, 30, 36, 40, 42, 42, 40, 36, 30, 22, 12.

Jesus Christ, this card is complicated. This math is probably the simplest part. But until I saw 3 = 3, 4, 3 instead of 3 = 3, 5, 6, I would never have guessed how convoluted they intended it to be. —
So here's what I'm still not getting: —
Interestingly, the benefit that this card gives does not always increase with an increasing number of spent power tokens (see @gumonshoe 's post above, strength added = n(X+1). Instead it has a "Maximum usefulness" after which the strength you get actually decreases! "What's the limit on how much I should spend?" you ask. The answer is half the number of power counters (rounded up if their's an odd number). —
im confused —